Optimal. Leaf size=92 \[ \frac{a x}{2 \left (a^2+b^2\right )}-\frac{a b^2 x}{\left (a^2+b^2\right )^2}+\frac{b \sin ^2(x)}{2 \left (a^2+b^2\right )}-\frac{a \sin (x) \cos (x)}{2 \left (a^2+b^2\right )}+\frac{a^2 b \log (a \cos (x)+b \sin (x))}{\left (a^2+b^2\right )^2} \]
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Rubi [A] time = 0.138902, antiderivative size = 92, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.389, Rules used = {3109, 2564, 30, 2635, 8, 3097, 3133} \[ \frac{a x}{2 \left (a^2+b^2\right )}-\frac{a b^2 x}{\left (a^2+b^2\right )^2}+\frac{b \sin ^2(x)}{2 \left (a^2+b^2\right )}-\frac{a \sin (x) \cos (x)}{2 \left (a^2+b^2\right )}+\frac{a^2 b \log (a \cos (x)+b \sin (x))}{\left (a^2+b^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 3109
Rule 2564
Rule 30
Rule 2635
Rule 8
Rule 3097
Rule 3133
Rubi steps
\begin{align*} \int \frac{\cos (x) \sin ^2(x)}{a \cos (x)+b \sin (x)} \, dx &=\frac{a \int \sin ^2(x) \, dx}{a^2+b^2}+\frac{b \int \cos (x) \sin (x) \, dx}{a^2+b^2}-\frac{(a b) \int \frac{\sin (x)}{a \cos (x)+b \sin (x)} \, dx}{a^2+b^2}\\ &=-\frac{a b^2 x}{\left (a^2+b^2\right )^2}-\frac{a \cos (x) \sin (x)}{2 \left (a^2+b^2\right )}+\frac{\left (a^2 b\right ) \int \frac{b \cos (x)-a \sin (x)}{a \cos (x)+b \sin (x)} \, dx}{\left (a^2+b^2\right )^2}+\frac{a \int 1 \, dx}{2 \left (a^2+b^2\right )}+\frac{b \operatorname{Subst}(\int x \, dx,x,\sin (x))}{a^2+b^2}\\ &=-\frac{a b^2 x}{\left (a^2+b^2\right )^2}+\frac{a x}{2 \left (a^2+b^2\right )}+\frac{a^2 b \log (a \cos (x)+b \sin (x))}{\left (a^2+b^2\right )^2}-\frac{a \cos (x) \sin (x)}{2 \left (a^2+b^2\right )}+\frac{b \sin ^2(x)}{2 \left (a^2+b^2\right )}\\ \end{align*}
Mathematica [C] time = 0.324497, size = 153, normalized size = 1.66 \[ -\frac{2 b \left (a^2+b^2\right ) \cos (2 x)-2 i b \left (b^2-3 a^2\right ) \tan ^{-1}(\tan (x))-2 \left (a^2+b^2\right ) (b \log (a \cos (x)+b \sin (x))+a x)-6 i a^2 b x-3 a^2 b \log \left ((a \cos (x)+b \sin (x))^2\right )-2 a^3 x+2 a^3 \sin (2 x)+6 a b^2 x+2 a b^2 \sin (2 x)+b^3 \log \left ((a \cos (x)+b \sin (x))^2\right )+2 i b^3 x}{8 \left (a^2+b^2\right )^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.069, size = 174, normalized size = 1.9 \begin{align*}{\frac{{a}^{2}b\ln \left ( a+b\tan \left ( x \right ) \right ) }{ \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{\tan \left ( x \right ){a}^{3}}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) }}-{\frac{a\tan \left ( x \right ){b}^{2}}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) }}-{\frac{{a}^{2}b}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) }}-{\frac{{b}^{3}}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) }}-{\frac{\ln \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ){a}^{2}b}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{\arctan \left ( \tan \left ( x \right ) \right ){a}^{3}}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{\arctan \left ( \tan \left ( x \right ) \right ) a{b}^{2}}{2\, \left ({a}^{2}+{b}^{2} \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.64151, size = 285, normalized size = 3.1 \begin{align*} \frac{a^{2} b \log \left (-a - \frac{2 \, b \sin \left (x\right )}{\cos \left (x\right ) + 1} + \frac{a \sin \left (x\right )^{2}}{{\left (\cos \left (x\right ) + 1\right )}^{2}}\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{a^{2} b \log \left (\frac{\sin \left (x\right )^{2}}{{\left (\cos \left (x\right ) + 1\right )}^{2}} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac{{\left (a^{3} - a b^{2}\right )} \arctan \left (\frac{\sin \left (x\right )}{\cos \left (x\right ) + 1}\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{\frac{a \sin \left (x\right )}{\cos \left (x\right ) + 1} - \frac{2 \, b \sin \left (x\right )^{2}}{{\left (\cos \left (x\right ) + 1\right )}^{2}} - \frac{a \sin \left (x\right )^{3}}{{\left (\cos \left (x\right ) + 1\right )}^{3}}}{a^{2} + b^{2} + \frac{2 \,{\left (a^{2} + b^{2}\right )} \sin \left (x\right )^{2}}{{\left (\cos \left (x\right ) + 1\right )}^{2}} + \frac{{\left (a^{2} + b^{2}\right )} \sin \left (x\right )^{4}}{{\left (\cos \left (x\right ) + 1\right )}^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.513713, size = 221, normalized size = 2.4 \begin{align*} \frac{a^{2} b \log \left (2 \, a b \cos \left (x\right ) \sin \left (x\right ) +{\left (a^{2} - b^{2}\right )} \cos \left (x\right )^{2} + b^{2}\right ) -{\left (a^{2} b + b^{3}\right )} \cos \left (x\right )^{2} -{\left (a^{3} + a b^{2}\right )} \cos \left (x\right ) \sin \left (x\right ) +{\left (a^{3} - a b^{2}\right )} x}{2 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13871, size = 205, normalized size = 2.23 \begin{align*} \frac{a^{2} b^{2} \log \left ({\left | b \tan \left (x\right ) + a \right |}\right )}{a^{4} b + 2 \, a^{2} b^{3} + b^{5}} - \frac{a^{2} b \log \left (\tan \left (x\right )^{2} + 1\right )}{2 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )}} + \frac{{\left (a^{3} - a b^{2}\right )} x}{2 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )}} + \frac{a^{2} b \tan \left (x\right )^{2} - a^{3} \tan \left (x\right ) - a b^{2} \tan \left (x\right ) - b^{3}}{2 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )}{\left (\tan \left (x\right )^{2} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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